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SOLUTION TO EXERCISE 17
SOLUTION TO EXERCISE 17
The diagram should look sort of like this:
| The critical point is labeled "X" and is
| where the temperature is 647 K and pressure
| X of 260 atm.
| \ /
| \ L / The triple point, where the three branches
p | \ / of the diagram meet, is at 273 K and 0.006 atm.
r | S \/
e | / G The slope of the line between solid and liquid
s | / must be negative, since the solid floats on the
s | / liquid. The other two branches have positive
u | / slope.
r | /
e |/
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temperature
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