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where the allele frequencies pj satisfy

image

We can rewrite hT as

image

First, we express the homozygote parameters image in terms of the heterozygote parameters image. Substituting Equations 4.4 into the equation

image

and noting that pi ¹ 0 leads to

image

Multiplying that by pi and summing over i enables us to define the mean

image

Thus, the weighted means of the homozygote and heterozygote parameters are equal.

We insert Equation 4.4b to deduce that

image

If the subpopulations are distinct and mating is random in each subpopulation, then FIT = FST , and hence image.



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