where the allele frequencies pj satisfy
We can rewrite hT as
First, we express the homozygote parameters in terms of the heterozygote parameters . Substituting Equations 4.4 into the equation
and noting that pi ¹ 0 leads to
Multiplying that by pi and summing over i enables us to define the mean
Thus, the weighted means of the homozygote and heterozygote parameters are equal.
We insert Equation 4.4b to deduce that
If the subpopulations are distinct and mating is random in each subpopulation, then FIT = FST , and hence .
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4 Population Genetics ."
The Evaluation of Forensic DNA Evidence . Washington, DC: The National Academies Press,
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