Yes, when the object is in freefall on Earth, gravity = a = 9.8m/s^2 down. Signs are optional but you could say -9.8n/s^s.
In 2D, the gravity is always 9.8m/s^2 down on the object.
It doesn't matter how the object is moving or thrown, gravity is always down.
The graph of the acceleration is the graph of the derivative of the v-graph. Find the slope at each second and graph it onto a new graph. The a-graph is not linear.
Wait, I think it was the d for the 4th second, from 3-4s. Because the first second is 0-1s, second second is for 1-2s, etc.
So
Vf=vo+at
V@3=5+9.8*3 and V@4=5+9.8*4
Vf^2=Vo^2+2ad
(V@4)^2=(V@3)^2+2*9.8*d
Find d